posted by anna .
a pet truck is moving at 25m/s north, a dog inside moves at 1.75 m/s at angle 35 degrees east of north. What is the velocity of the dog relative to the road?
let s be the speed of the dog
s^2 = 25^2 + 1.75^2 - 2(25)(1.75)cos 145°
s = 26.45m/s
Let θ be the direction of travel
sinθ/1.75 = sin145°/26.45
θ = 2.17°
So, the dog's velocity is 26.45 m/s at N2.17°E