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a pet truck is moving at 25m/s north, a dog inside moves at 1.75 m/s at angle 35 degrees east of north. What is the velocity of the dog relative to the road?

  • physics -

    let s be the speed of the dog

    s^2 = 25^2 + 1.75^2 - 2(25)(1.75)cos 145°
    s = 26.45m/s

    Let θ be the direction of travel

    sinθ/1.75 = sin145°/26.45
    θ = 2.17°

    So, the dog's velocity is 26.45 m/s at N2.17°E

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