Water flows through a 1.2 cm diameter pipe into a 155 L bathtub, which it fills in 8 min.What is the speed of the water in the pipe?

We know our diameter is 1.2cm so our radius is 0.6 cm or 0.006 m. Now we find our volume flow rate, Q. so 155l/8min * 1min/60s *1m^3/1000L = 3.2292*10^-4 m^3/s.

Velocity= Volume flow rate/Area
V=Q/A
V= 3.2292*10^-4 m^3/s

sorry. here is complete answer.

We know our diameter is 1.2cm so our radius is 0.6 cm or 0.006 m. Now we find our volume flow rate, Q. so 155l/8min * 1min/60s *1m^3/1000L = 3.2292*10^-4 m^3/s.
Velocity= Volume flow rate/Area
V=Q/A
V= 3.2292*10^-4 m^3/s/ pie*((6*10^-3)^2)
V=2.8 m/s

To find the speed of the water in the pipe, we can use the equation:

Speed = Volume / Time

First, let's convert the diameter of the pipe from centimeters to meters:

1.2 cm = 0.012 m (since 1 cm = 0.01 m)

Next, let's calculate the cross-sectional area of the pipe using the formula for the area of a circle:

Area = π * (radius)^2

The radius of the pipe is half the diameter, so:

Radius = 0.012 m / 2 = 0.006 m

Area = π * (0.006 m)^2 = 0.0001130973 m^2 (rounded to 10 decimal places)

Now, we need to calculate the volume of water that flows into the bathtub in 8 minutes. Since the water flows through the pipe, we can assume that the volume of water entering the bathtub is equal to the volume of water flowing through the pipe.

Volume = 155 L

However, we need to convert this volume from liters to cubic meters:

1 L = 0.001 m^3

Volume = 155 L * 0.001 m^3/L = 0.155 m^3

Now, we can calculate the speed of the water in the pipe:

Speed = 0.155 m^3 / 8 min

But we need to convert the time from minutes to seconds:

1 min = 60 s

So, 8 min = 8 min * 60 s/min = 480 s

Finally, we can calculate the speed:

Speed = 0.155 m^3 / 480 s

Speed ≈ 0.000323 m^3/s (rounded to 6 decimal places)

Therefore, the speed of the water in the pipe is approximately 0.000323 m^3/s.