precalculus

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Find (a) the equation of a line that is parallel to the given line and includes the given point, and (b) the equation of a line that is perpendicular to the given line through the given point. Write both answers in slope-intercept form. (c) Graph both of these lines on the same axes and submit your graph. Please show all of your work.

y = -2x + 3, (-2, -3)

  • precalculus -

    Just use the point-slope form and then rearrange terms to slope-intercept form:

    The line through (-2,-3) with slope -2:
    (y-(-3))/(x-(-2)) = (y+3)/(x+2) = -2

    The other line has slope -1/(-2) = 1/2.
    Go for it.

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