Q A man throws a ball weighing 500g vertically upwards witha speed of 10m/s.
1) what will be its initial momentum?
2) What would be its momentum at the highest point of his flight?
See previous post.
m=5kg,speed=10m/s,p=m.v=1kgm
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To calculate the answers to these questions, we can use the principle of conservation of momentum.
1) The initial momentum of the ball can be calculated using the formula:
Momentum = mass x velocity
Given that the ball weighs 500g (or 0.5kg) and has an initial velocity of 10m/s, we can substitute these values into the formula:
Momentum = 0.5kg x 10m/s = 5kg·m/s
Therefore, the initial momentum of the ball is 5 kg·m/s.
2) At the highest point of the ball's flight, its vertical velocity will be zero. However, its momentum will not be zero because it will still have horizontal velocity (assuming air resistance is negligible).
Since there is no vertical component of velocity, it means that only the horizontal component of the ball's velocity remains. Therefore, its momentum at the highest point will be the same as its initial momentum.
So, the momentum at the highest point of the ball's flight is also 5 kg·m/s.
To summarize:
1) The initial momentum of the ball is 5 kg·m/s.
2) The momentum at the highest point of the ball's flight is also 5 kg·m/s.