Simplify:
(a) 4�ã7 (2�ã3 +3�ã6 -�ã7 )
(b) (3�ã7 -�ã2 )squared
(c) (16�ã24)/(4�ã96)
(d) 7/(�ã20 ) - 4/(�ã12)
(e) (3�ã2)/(�ã12) - (5�ã3)/(�ã8 )
I will assume your ã is supposed to be a √
To do these, you should know the basic laws for radicals, such as
√a x √b = √(ab) etc.
I will do the first and last, give the others a shot
a)
4√7(2√3 + 3√6 - √7)
= 8√21 + 12√42 - 4√49
= 8√21 + 12√42 - 28
e)
3√2/√12 - 5√3/√8
= 3√2/(2√3) - 5√3/(2√2)
= 3√2/(2√3)(√3/√3) - 5√3/(2√2)(√2/√2)
= 3√6/6 - 5√6/4
= √6/2 - 5√6/4
= 2√6/4 - 5√6/4
= -3√6/4