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Mathematics
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solve for 9x-21y=28 -9x+21y=21 in elimination method
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These equations are not solvable. If you add the two equations, you get 0 = 49.
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In the term 21y, what is ther literal coefficient?
a. 2 b. 21 c. 21y d. y I believe it is y
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I mean the answer is B
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4x+5y=27
x=26-4y 4(26-4y) + 5y = 27 104 - 16y+ 5y = 27 -21y = - 77 21y = 77 y = 77/31 Now, I’m suppose to return to the 2nd
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-16y+5y=-11y, not -21y..I think that's your mistake
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solve gauss jordan elimination
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hard to type up on here. Try this nice applet:
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Solve for x and y:
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1- Simplify the radical expression: √250h^4k^5
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Top answer:
factor out perfect squares. #1. √250h^4k^5 = √25*10*h^4*k^4*k = √(25h^4k^4)*10k = 5h^2k^2
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3x + 14y = 5xy
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1.Divide the two equations by xy 2.You will now have two equations. 3.Solve it by multiplying and
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Use the Substitution method to solve the system of equations.
3x + y = 5 4x - 7y = -10 multiply first equation by 4 multiply
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§ur13
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Can someone please help me with math problem and explain to me step by step how to solve it so I will know how solve other
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It would help if you proofread your questions before you posted them.
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What is y if 6y+1=21y+13
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-4/5
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y^4-10y^3+21y^2
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y^2(y^2-10y+21) that help?
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is this correct
7x+21y-7=7(x+3y-1)
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