radium-266 may emit a photon of light with a frequency of 4.5x 10^19 s^-1 when it undergoes nuclear fission. what is the wavelength in pm of this photon?
c = frequency x wavelength.
Solve for wavelength in meters.
Convert to pm. 10^12 pm = 1m
thank you
To determine the wavelength of a photon, you can use the equation:
wavelength = speed of light / frequency
However, before we can proceed, we need to convert the frequency to Hz (hertz). The given frequency is already in hertz (s^-1).
Now we can plug in the values into the equation:
wavelength = speed of light / frequency
wavelength = (3.0 x 10^8 m/s) / (4.5 x 10^19 s^-1)
Let's calculate this:
wavelength = (3.0 x 10^8 m/s) / (4.5 x 10^19 s^-1)
= 6.67 x 10^-12 m
The wavelength is expressed in meters (m). To convert it to picometers (pm), we multiply by a conversion factor:
1 m = 1 x 10^12 pm
Let's convert the wavelength to picometers:
wavelength in pm = (6.67 x 10^-12 m) * (1 x 10^12 pm/1 m)
= 6.67 pm
Therefore, the wavelength of the photon emitted by radium-266 during nuclear fission is approximately 6.67 picometers (pm).