15. Records at a high school indicate that each year for the past five years, 120 of the 1,500 students were absent on the first day of hunting season. What is the likelihood that a particular student will be absent on the first day of hunting season this year? (Points: 5)
0.08
0.12
0.18
0.20
We do not do your homework for you. Although it might take more effort to do the work on your own, you will profit more from your effort. We will be happy to evaluate your work though.
Include your best answer.
1500.00
To find the likelihood that a particular student will be absent on the first day of hunting season this year, we need to calculate the average proportion of absent students over the past five years.
Given that there were 120 absent students out of 1500 each year for the past five years, we can calculate the average proportion of absent students as follows:
Average proportion = (Total number of absent students) / (Total number of students)
Total number of absent students = 120 * 5 = 600
Total number of students = 1500
Average proportion = 600 / 1500 = 0.4
Therefore, the average proportion of absent students over the past five years is 0.4.
Next, to find the likelihood that a particular student will be absent this year, we can multiply the average proportion by 100 to get the percentage:
Likelihood = Average proportion * 100 = 0.4 * 100 = 40%
So, the likelihood that a particular student will be absent on the first day of hunting season this year is 40%, which can be represented as 0.40.
Therefore, the correct answer is not provided in the given options.