In the reaction:Zn+ 2HCL>ZnCl2+h2.What mass ZnCl2 is produced when 10g of zn reacted
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To find the mass of ZnCl2 produced when 10g of Zn reacts, you need to use stoichiometry. Stoichiometry is the calculation of reactants and products in a chemical reaction based on the balanced equation.
First, start with the balanced equation:
Zn + 2HCl → ZnCl2 + H2
The stoichiometric ratio between Zn and ZnCl2 is 1:1, which means that for every one mole of Zn that reacts, one mole of ZnCl2 is produced.
To calculate the amount of ZnCl2 produced, follow these steps:
1. Convert the given mass of Zn to moles using its molar mass.
- The molar mass of Zn is 65.38 g/mol.
10 g Zn × (1 mol Zn / 65.38 g Zn) = 0.153 mol Zn
2. Use the stoichiometric ratio to find the moles of ZnCl2 produced.
- The stoichiometric ratio is 1:1 between Zn and ZnCl2.
0.153 mol Zn × (1 mol ZnCl2 / 1 mol Zn) = 0.153 mol ZnCl2
3. Convert the moles of ZnCl2 to its mass using its molar mass.
- The molar mass of ZnCl2 is 136.29 g/mol.
0.153 mol ZnCl2 × (136.29 g ZnCl2 / 1 mol ZnCl2) = 20.86 g ZnCl2
Therefore, when 10g of Zn reacts, approximately 20.86g of ZnCl2 is produced.