In the reaction:Zn+ 2HCL>ZnCl2+h2.What mass ZnCl2 is produced when 10g of zn reacted
Calculate the number of moles of Zn from
M=10g/molar mass of Zn
calculate molar mass of ZnCl2
mass produced is then
M x molar mass of ZnCl2
Is it single replacement reaction?
To find the mass of ZnCl2 produced when 10g of Zn reacts, we need to use the stoichiometry of the reaction. The balanced chemical equation is:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that 1 mole of Zn reacts with 2 moles of HCl to produce 1 mole of ZnCl2. We can use the molar mass of Zn to convert 10g of Zn to moles.
1. Find the molar mass of Zn:
The atomic mass of Zn is 65.38 g/mol.
2. Convert 10g of Zn to moles:
moles of Zn = mass / molar mass
moles of Zn = 10g / 65.38 g/mol
3. Use the stoichiometry from the balanced equation to determine the moles of ZnCl2 produced:
According to the balanced equation, 1 mole of ZnCl2 is produced for every mole of Zn that reacts. Therefore, the moles of ZnCl2 produced will be the same as the moles of Zn.
4. Convert moles back to grams of ZnCl2:
mass of ZnCl2 = moles of ZnCl2 * molar mass of ZnCl2
To find the molar mass of ZnCl2, we need to calculate the masses of Zn (65.38 g/mol) and Cl (35.45 g/mol) and add them together:
molar mass of ZnCl2 = 65.38 g/mol + 2 * 35.45 g/mol
molar mass of ZnCl2 = 136.28 g/mol
mass of ZnCl2 = moles of ZnCl2 * molar mass of ZnCl2
mass of ZnCl2 = 10g / 65.38 g/mol * 136.28 g/mol
Calculating the above equation will give you the mass of ZnCl2 produced when 10g of Zn reacts.
To find the mass of ZnCl2 produced when 10g of Zn reacts, we need to use stoichiometry – the conversion of moles and balanced chemical equations.
Here's how to approach it:
Step 1: Write and balance the chemical equation.
The balanced chemical equation for the reaction given is:
Zn + 2HCl → ZnCl2 + H2
Step 2: Calculate the molar mass.
Find the molar mass of ZnCl2 by summing up the atomic masses of its constituent elements:
Zn: 65.38 g/mol
Cl: 35.45 g/mol (there are two Cl atoms)
ZnCl2: 65.38 + (2 × 35.45) = 136.28 g/mol
Step 3: Convert the mass of Zn to moles.
Use the molar mass of Zn (65.38 g/mol) to determine the number of moles:
10 g Zn × (1 mol Zn / 65.38 g Zn) = 0.153 moles Zn
Step 4: Use the balanced equation to establish the mole ratio.
From the balanced equation, we can see that the mole ratio between Zn and ZnCl2 is 1:1. This means that for every 1 mole of Zn, we get 1 mole of ZnCl2.
Step 5: Calculate the moles of ZnCl2 produced.
Since the mole ratio is 1:1, the moles of ZnCl2 produced will also be 0.153 moles.
Step 6: Convert moles of ZnCl2 to mass.
Multiply the moles of ZnCl2 by the molar mass of ZnCl2 to get the mass:
0.153 moles ZnCl2 × (136.28 g ZnCl2 / 1 mol ZnCl2) = 20.87 g ZnCl2
Therefore, when 10g of Zn reacts, approximately 20.87g of ZnCl2 will be produced.