Calculus

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Find The Derivative
y= 9e^(x)/ 2e^(x)+ 1
Please Show Work

  • Calculus -

    I assume that's 9e^x/(2e^x + 1)
    Otherwise, y = 9/2 + 1 = 11/2, which is not very interesting.

    y' = [9e^x (2e^x + 1) - 9e^x * 2e^x]/(2e^x + 1)^2

    y' = [18e^(2x) + 9e^x - 18e^(2x)]/(2e^x + 1)^2

    y' = 9e^x/(2e^x + 1)^2

    Hmm. How about that?

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