Calculus
posted by Brett .
Find The Derivative
y= 9e^(x)/ 2e^(x)+ 1
Please Show Work

I assume that's 9e^x/(2e^x + 1)
Otherwise, y = 9/2 + 1 = 11/2, which is not very interesting.
y' = [9e^x (2e^x + 1)  9e^x * 2e^x]/(2e^x + 1)^2
y' = [18e^(2x) + 9e^x  18e^(2x)]/(2e^x + 1)^2
y' = 9e^x/(2e^x + 1)^2
Hmm. How about that?
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