calculus
posted by lee .
Suppose the area of a square is increasing with time.At the time when the side of the square is 4 meters and the change in area is 2 sq meters per min, find the change in the length of the side of the square.

a = s^2
da/dt = 2s ds/dt
2 = 2(4) ds/dt
2 = 8 ds/dt
1/4 = ds/dt
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