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Find the sum of the first 12 terms of the sequences given in #1.

a.f(n) = 5*(2)^(n-1) ; for n = 1,2,3,4,…
b.a1 = 1/3 ; an+1 = = 3*an

  • Math -

    a.
    f(n)=5*2^(n-1)
    f(1)=5*2^(1-1)=5*2^0=5
    f(2)=5*2^(2-1)=5*2^1=10
    f(3)=5*2^(3-1)=5*2^2=20
    f(4)=5*2^(n-1)=5*2^3=40
    ...

    b.
    a1=1/3
    a2=a1+1=3*a1=3*(1/3)=1
    a3=a2+1=3*a2=3*1=3
    ...


    get the idea?

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