what is the boiling point of an aqueous solution that freezes at
-67 degrees C?
I was given this answer
What is 100+6.7 (1.86/.52) ?
so 100+6.7 = 106.7
1.86/.52 = 3.58
is the .52 the Kb
I got the answer in the book I just don't understand how they got to it.
-.52 is the Kf. 1.86 is the Kb You need to understand the signs.
first, find the molality.
Now the bp
Thanks I under stank Kf but in my book it says that Kf is 0.512