Is 450g of oxygen enough to burn 125g of butane according to the following equation? C4H10 + O2 ---> CO2 + H2O? show why or why not?
Balanced the equation.
2C4H10 + 14O2 ==> 8CO2 + 10H2O
Convert 125 g oxygen to butane.
450 g oxygen/32 = moles oxygen = about 14 moles but you need to be more accurate.
Now use the coefficients in the balanced equation and convert moles O2 to moles C4H10 this way.
14 moles O2 x (2 moles C4H10/14 moles O2) = 14 x (2/14) = about 2 moles C4H10. Convert that to grams C4H10
moles x molar mass = grams. I get approximately 116 g C4H10 which means you can burn about 116 g butane so that is almost but not quite enough oxygen.
3=1
To determine whether 450g of oxygen is enough to burn 125g of butane (C4H10), we need to compare the stoichiometry (molar ratios) of oxygen to butane in the reaction equation.
The balanced equation for the combustion of butane is:
C4H10 + O2 → CO2 + H2O
According to the equation, for every 1 mole of butane (C4H10) consumed, we need a certain number of moles of oxygen (O2). This ratio can be derived from the coefficients of the balanced equation.
The balanced equation shows that the stoichiometric ratio between butane and oxygen is 1:13. This means that for every 1 mole of butane, 13 moles of oxygen are required.
To determine the amount of oxygen needed to burn 125g of butane, we need to convert the mass of butane to moles. The molar mass of butane (C4H10) is 58.12 g/mol. Therefore, 125g of butane is:
125g / 58.12 g/mol = 2.15 moles of butane
Now, using the stoichiometric ratio, we can calculate the moles of oxygen required to burn 2.15 moles of butane:
2.15 moles of butane × (13 moles of O2 / 1 mole of butane) = 27.95 moles of O2
To determine whether 450g of oxygen is enough, we need to convert the mass of oxygen to moles. The molar mass of oxygen (O2) is 32 g/mol. Therefore, 450g of oxygen is:
450g / 32 g/mol = 14.06 moles of O2
Comparing the moles of oxygen required (27.95 moles) to the moles of oxygen available (14.06 moles), we can see that the 450g of oxygen is not enough to burn 125g of butane. We would need approximately twice the amount of oxygen (27.95 moles) to completely burn 2.15 moles of butane.