How many grams of KCl would be produced from the complete decomposition of 2.75g of KClO3?
Here is a worked example right down your line.
http://www.jiskha.com/science/chemistry/stoichiometry.html
To determine the number of grams of KCl produced from the complete decomposition of KClO3, we need to consider the balanced chemical equation for the reaction. The equation is as follows:
2 KClO3 -> 2 KCl + 3 O2
From the balanced equation, we can see that 2 moles of KClO3 react to produce 2 moles of KCl. To find the molar mass of KClO3, KCl, and O2, we need to refer to the periodic table:
- Molar mass of KClO3: 39.10 g/mol (K) + 35.45 g/mol (Cl) + 3 * 16.00 g/mol (O) = 122.55 g/mol
- Molar mass of KCl: 39.10 g/mol (K) + 35.45 g/mol (Cl) = 74.55 g/mol
Now we can calculate the number of moles of KClO3:
Number of moles of KClO3 = Mass of KClO3 / Molar mass of KClO3
= 2.75 g / 122.55 g/mol
≈ 0.0224 mol
According to the balanced equation, 2 moles of KClO3 produce 2 moles of KCl. Therefore, using the stoichiometry of the reaction, we can calculate the number of moles of KCl:
Number of moles of KCl = Number of moles of KClO3 * (2 moles KCl / 2 moles KClO3)
= 0.0224 mol * (2 mol KCl / 2 mol KClO3)
= 0.0224 mol
Finally, we can determine the mass of KCl produced:
Mass of KCl = Number of moles of KCl * Molar mass of KCl
= 0.0224 mol * 74.55 g/mol
≈ 1.67 g
Therefore, approximately 1.67 grams of KCl would be produced from the complete decomposition of 2.75 grams of KClO3.