algebra 2
posted by takeidra .
the perimeter of a triangle is 49 centimeters. find the lenghts of its sides, if the longest side is 9 centimeters longer than the shorter side, and the remaining side is 4 centimeters longer than the shorter side.

49=x+(x+9)+(x+4)
49=3x+13
36=3x
12+x
so one side is 12cm, on is 16cm and one is 21cm
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