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Ethanol, C2H5OH, MW = 46.1 g/mole, is a popular alternative to hydrocarbon fuels. Calculate the grams of ethanol that must be burned to provide 4082 kJ of heat.

  • Chemistry -

    C2H5OH + 3O2 ==> 2CO2 + 3H2O
    Look up delta H for the combustion.
    Then DHcmb x (#g/46.1) = 4,082,000.
    Solve for #grams.

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