Statistics

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In a city with no cars of mixed color, 30% of the cars on the road are brown. Forty percent are either brown or green, and 10% are white.
a.) What is the probability that a randomly selected car is green?

b.) What is the probability that a randomly selected car is not brown, green, or white?


Thanks a bunch for whoever can help!?

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    How many cars were there altogether?

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    It doesn't say how many cars in total there were. Im guessing that in total these cars added up to 100%.

  • Statistics -

    a.)1/5
    b.)1/4

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    Is there anyway that you can show me how you got that so I can understand a little better? Thanks!

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    a.)40% of cars are either brown or green. Divide that by two since there are two colors. You get 20. Put that over 100=20/100. Reduce it to 2/10 which reduces to 1/5.
    b.)Add all the percents together to get 80%. Subtract it from 100. 100-80=20. 20/100=1/5. So the actual answer to b is 1/5. Sorry, my mistake. :P

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    Thanks a bunch!

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    No problem.(:

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    What about the undefined remaining 20%?

    30% + 40% + 10% = only 80%

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    She DID do that.

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