Questions LLC
Login
or
Sign Up
Ask a New Question
Mathematics
Algebra
Trigonometric Equations
verify the following
1+1/csc^2x-1=sec^2x
1 answer
1 + 1/(csc^2 - 1)
1 + 1/cot^2
1 + tan^2
sec^2
You can
ask a new question
or
answer this question
.
Related Questions
Which of the following expressions is equivalent to (cos(3x))/sin(x)cos(x))?
csc(x) cos(2x) - sec(x) sin(2x) sec(x) cos(2x) -
What is a simplified form of the expression [sec^2x-1]/[(sinx)(secx)]?
a. cot x b. csc x c. tan x***** d. sec x tan x I think
Prove the trigonometric identity.
tan x+cot x/csc x cos x=sec^2 x __= sec^2x __= sec^2x __ = sec^2x __= sec^2x __ = sec^2x
1.) Which of the following polar equations is equivalent to the parametric equations below?
x=t^2 y=2t A.)
What is a simplified form of the expression sec^2x-1/sin x sec x ?
a)cot x b)csc x c)tan x d)sec x tan x Please help me :(
1.) Find an expression equivalent to sec theta sin theta cot theta csc theta.
tan theta csc theta sec theta ~ sin theta 2.) Find
1. Simplify the expression.
[csc^2(x-1)]/[1+sin x] a. csc x+1 b. csc x(csc x-1) c. sin^2 x-csc x**** d. csc^2 x-cos xtan x 2.
1. (sec^2x-6tanx+7/sec^2x-5)=(tanx-4/tanx+2)
2. (sin^3A+cos^3A/sinA+cosA)=1-sinAcosA 3. csc^6x-cot^6x+1+3csc^2xcot^2x please help
I am having trouble with this problem.
sec^2(pi/2-x)-1= cot ^2x I got : By cofunction identity sec(90 degrees - x) = csc x secx
For a standard-position angle determined by the point (x, y), what are the values of the trigonometric functions?
For the point