Algebra

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Write the slope-intercept equation for the line that passes through (-3,-15)and is perpendicular to -6x+8y=3

  • Algebra -

    First, let's solve the equation for y to determine the slope of the line.

    -6x + 8y = 3

    8y = 6x + 3

    y = (6/8)x + 3/8 = (3/4)x + 3/8

    Slope = 3/4

    The slope of a line perpendicular to this one must be its negative reciprocal, or -4/3.

    Now, use the point-slope form to find the other line:

    y - y1 = m(x - x1)
    y - (-15) = -4/3 [x - (-3)]
    y + 15 = -4/3 (x + 3)
    y + 15 = (-4/3)x - 4
    y = (-4/3)x - 4 - 15
    y = (-4/3)x - 19

    And there you have it! By showing you the steps, I hope this will help with other problems of this type.

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