Math
posted by Amy .
suppose u and v are functions of x that are differentiable at x=2 and
that u(2) =3, u'(2) = 4, v(2) = 1, and v'(2)
find values of derivatives at x = 2
(d/dx)(uv) = ?
I would like to know how to set this up because I'm only used to getting problems that want the d/dx given ex: y=2x+1 so I was confused for this
The answer is 2 but how do I set this up?

This is just the product rule.
d/dx(uv) = du/dx * v + u * dv/dx
when x=2,
d/dx(uv) = (4)(1) + (3)(2) = 4+6 = 2
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