posted by Amy .
suppose u and v are functions of x that are differentiable at x=2 and
that u(2) =3, u'(2) = -4, v(2) = 1, and v'(2)
find values of derivatives at x = 2
(d/dx)(uv) = ?
I would like to know how to set this up because I'm only used to getting problems that want the d/dx given ex: y=2x+1 so I was confused for this
The answer is 2 but how do I set this up?
This is just the product rule.
d/dx(uv) = du/dx * v + u * dv/dx
d/dx(uv) = (-4)(1) + (3)(2) = -4+6 = 2