In 1000BASE-X, a frame of 64 bytes is fi rst block coded
with 8B/10B before transmitting. Suppose the propagation
speed is 2 × 10 8 . What is the frame “length” in
“meters”? (Suppose the cable is 500 m long.)
To calculate the frame "length" in meters, we need to consider the time it takes for the frame to propagate through the cable.
First, let's find the time it takes for the frame to propagate through the cable. We can use the formula:
Propagation time = Distance / Propagation speed
In this case, the distance is given as 500 meters, and the propagation speed is given as 2 × 10^8 meters per second. Substituting these values into the formula:
Propagation time = 500 / (2 × 10^8)
Next, we need to determine the time it takes to transmit the frame. The frame is initially block coded with 8B/10B before transmitting. This coding means that for every 8 bytes of data, 10 bytes are transmitted. So, the transmission time can be calculated using the formula:
Transmission time = (Frame size / (8/10)) / Transmission speed
In this case, the frame size is given as 64 bytes, and the transmission speed is not provided. Please provide the transmission speed to continue.
Once the transmission time is calculated, we can add it to the propagation time to find the total time it takes for the frame to propagate through the cable and be transmitted. We can then convert this time to meters by multiplying it by the speed of light.
Could you please provide the transmission speed?