when 2.13 moles of C3H8 burn in excess oxygen, how many moles of CO2 will be formed? Assume this is a complete combustion
balance the equation.
C3H8+ 5O2 >>4H2O + 3CO2
moles O2= 5/1 * 2.13 moles
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To determine the moles of CO2 formed when 2.13 moles of C3H8 burn in excess oxygen, we need to use the balanced equation for the combustion reaction of C3H8.
The balanced equation is as follows:
C3H8 + 5O2 -> 3CO2 + 4H2O
From the balanced equation, we can see that for every 1 mole of C3H8, 3 moles of CO2 are produced.
Therefore, to calculate the moles of CO2 produced, we can use the following conversion:
Moles of CO2 = Moles of C3H8 * (Moles of CO2 / Moles of C3H8)
Moles of CO2 = 2.13 moles * (3 moles of CO2 / 1 mole of C3H8)
Moles of CO2 = 2.13 moles * 3
Moles of CO2 = 6.39 moles
So, when 2.13 moles of C3H8 burn completely in excess oxygen, 6.39 moles of CO2 will be formed.
To determine the number of moles of CO2 formed during the complete combustion of 2.13 moles of C3H8, we need to use the stoichiometry of the balanced chemical equation for the combustion reaction.
The balanced chemical equation for the combustion of C3H8 is:
C3H8 + 5O2 -> 3CO2 + 4H2O
From the equation, we can see that for every 1 mole of C3H8, 3 moles of CO2 are produced. Therefore, to find the number of moles of CO2 produced when 2.13 moles of C3H8 burn, we can use the following calculation:
Number of moles of CO2 = (2.13 moles C3H8) x (3 moles CO2 / 1 mole C3H8)
Now, let's do the math:
Number of moles of CO2 = (2.13 moles) x (3 moles CO2 / 1 mole)
Number of moles of CO2 = 6.39 moles
Therefore, when 2.13 moles of C3H8 are burned in excess oxygen, 6.39 moles of CO2 will be formed.