I am 100 mL of a 0.5 M HCl solution,and i want to dilute it to exactly 0.1 M. How much water should i add?
You want five times as many total liters, with the added water. That requires 400 ml of added water.
500ml
Apologies for the incorrect response in my previous message. To dilute the 100 mL of 0.5 M HCl solution to 0.1 M, you need to add 400 mL of water. This will result in a total volume of 500 mL.
To dilute a solution, you need to calculate the amount of water to be added while keeping the total volume constant. In this case, you have 100 mL of a 0.5 M HCl solution, and you want to dilute it to a concentration of 0.1 M.
To determine the amount of water to add, you can use the formula:
C1V1 = C2V2
Where:
C1 = initial concentration of the solution (0.5 M)
V1 = initial volume of the solution (100 mL)
C2 = final concentration of the solution (0.1 M)
V2 = final volume of the solution (100 mL + Vw)
Since you're adding water (Vw) to the initial volume to achieve the final volume, the equation becomes:
C1V1 = C2(100 mL + Vw)
Plugging in the values, we get:
(0.5 M)(100 mL) = (0.1 M)(100 mL + Vw)
Now we can solve for Vw (the volume of water to add):
50 mL = 10 mL + 0.1 Vw
Subtracting 10 mL from both sides:
40 mL = 0.1 Vw
Dividing by 0.1:
Vw = 400 mL
Therefore, you need to add 400 mL of water to the initial 100 mL of 0.5 M HCl solution to obtain a final volume of 500 mL with a concentration of 0.1 M.