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Physics (4)

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A 4.0-kg particle is moving horizontally with a speed of 5.0 m/s when it strikes a vertical wall. The particle rebounds with a speed of 3.0 m/s. What is the magnitude of the impulse delivered to the particle?

  • Physics (4) -

    I will help with this, then you do the rest.

    impulse = change in momentum = force * time

    initial momentum = 4*5 = 20
    final momentum = 4*-3 = -12

    change = -12 - 20 = -32
    magnitude of change of momentum = impulse = 32

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