# Calculus

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(y/(x+9y))= (x^2)-7

at the point (1, -6/55)

Use implicit differentiation to find the slope of the tangent line to the curve

• Calculus -

cross-multiply first

y = x^3 - 7x + 9x^2y - 63y
y' = 3x^2 - 7 + 9x^2y' + 18xy - 63y' , where y' = dy/dx

64y' - 9x^2y' = 3x^2 + 18xy-7
y' = dy/dx = (3x^2 + 18xy - 7)/(64 - 9x^2)

I will leave it up to you to do the remaining arithmetic

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