calculus

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5) Find the points on the curve below at which the tangent is horizontal. Use n as an arbitrary integer. (Select all that apply.)

y=Sin(x) / 2+ Cos (x)

  • calculus -

    y' = cosx/2 - sinx
    y'=0 where cosx = 2sinx

    That is, where tanx = 1/2

    So, if t = arctan(1/2) the tangent line is horizontal at

    x = t + nπ

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