# calculus

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5) Find the points on the curve below at which the tangent is horizontal. Use n as an arbitrary integer. (Select all that apply.)

y=Sin(x) / 2+ Cos (x)

• calculus -

y' = cosx/2 - sinx
y'=0 where cosx = 2sinx

That is, where tanx = 1/2

So, if t = arctan(1/2) the tangent line is horizontal at

x = t + nπ

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