A 71.0 kg person steps on a scale in an elevator. The scale reads 722 N. What is the magnitude of the acceleration of the elevator?
F = ma
that's wrong ^
To find the magnitude of the acceleration of the elevator, we need to use Newton's second law of motion, which states that the net force acting on an object is equal to its mass multiplied by its acceleration:
F = m * a,
where F is the force, m is the mass, and a is the acceleration.
In this case, the force acting on the person is the reading on the scale, which is 722 N, and the mass of the person is 71.0 kg.
We can rearrange the equation to solve for the acceleration:
a = F / m.
Substituting the values into the equation, we get:
a = 722 N / 71.0 kg ≈ 10.18 m/s^2.
Therefore, the magnitude of the acceleration of the elevator is approximately 10.18 m/s^2.