posted by Anonymous .
A stationary bicycle is raised off the ground, and its front wheel (m = 1.3 kg) is rotating at an angular velocity of 14.0 rad/s (see the drawing). The front brake is then applied for 3.0 s, and the wheel slows down to 2.7 rad/s. Assume that all the mass of the wheel is concentrated in the rim, the radius of which is 0.33 m. The coefficient of kinetic friction between each brake pad and the rim is ìk = 0.85. What is the magnitude of the normal force that each brake pad applies to the rim?
Torque = (moment of inertia)*(angular deceleration rate)
Solve for torque and relate that to the brake pads force.
Torque = 2*(normal force)*0.85*R