(5) In this experiment MnO4-is reduced to Mn
2+ by the unknown. What is the equivalent
weight of MnO4-
for this experiment? 52.68
(6) How many equivalents of electrons were transferred from the unknown solution?
(7) What is the Normality of the 1.00 mL of the unknown solution?
(8) If 2 moles of electrons are required to oxidize 1 mole of unknown, what is the molarity of
the unknown solution?
(9) What piece of data is necessary to calculate the unknown’s equivalent weight
KMnO4 .0097 M
Amount of unknown 1 ml
Change in volume 25 ml
(5) The equivalent weight of the KMnO4 is 158.034/5 = about 31.
I can't help you with the others because you didn't include all of the informatin from the experiment.
To calculate the answers to these questions, we need to understand some key concepts:
1. Equivalent weight: The equivalent weight of a substance is the molecular weight divided by the number of electrons transferred in the reaction.
2. Electrons transferred: In a redox reaction, electrons are transferred between species. The number of electrons transferred is equal to the change in oxidation state of the species involved.
3. Normality: Normality is a measure of concentration, representing the number of equivalents of solute per liter of solution.
4. Molarity: Molarity is another measure of concentration, representing the number of moles of solute per liter of solution.
Now, let's answer the questions one by one:
(5) To determine the equivalent weight of MnO4-, we need to know the number of electrons transferred in the reaction. From the given information, we know MnO4- is being reduced to Mn2+, which corresponds to a gain of 5 electrons. The molar mass of MnO4- is 52.68 g/mol. Therefore, the equivalent weight of MnO4- is 52.68 g/mol divided by 5, which is 10.54 g.
(6) The number of equivalents of electrons transferred can be calculated by dividing the moles of electrons transferred by the valence, which represents the number of electrons transferred per mole of the unknown substance. Since the valence is not provided in the given information, we cannot determine the number of equivalents of electrons transferred.
(7) The normality of the 1.00 mL of the unknown solution cannot be directly determined from the given information. We need the concentration of the unknown solution in terms of equivalents/liter to calculate normality.
(8) If 2 moles of electrons are required to oxidize 1 mole of the unknown substance, we cannot directly calculate the molarity of the unknown solution. We need the concentration of the unknown solution in terms of moles/liter.
(9) To calculate the unknown's equivalent weight, we need the number of electrons transferred in the reaction, which is not provided in the given information.
In summary, while we can determine the equivalent weight of MnO4- (question 5), we lack the necessary information to answer questions 6, 7, 8, and 9 accurately. Additional data is required to calculate these values.