# Calculus

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Find the point on the line -3 x + y + 4 =0 which is closest to the point ( -5, 0 ).

• Calculus -

distance=sqrt((x+5)^2+ (y)^2)

but y=3x-4
distance= sqrt((x+5)^2 + (3x-4)^2)

I think it will be easier to do this..
distance^2=((x+5)^2+(3x-4)^2) then take the deravative

2distane*ddistan/dx=0=2(x+5)+2(3x-4)*3

or x+5=-9x+12 check that, then solve for x, then solve for y on the line

check my work, I did it all in my head and on the keyboard.

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Ola, I'm not understanding this question, any assistance?

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