# Alg. II

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Factor completely:

54+16x^3

• Alg. II -

54 + 16x^3
2(8x^3 + 27)
then recall the how we factor sum of two cubes:
a^3 + b^3 = (a+b)(a^2 - ab + b^2)
therefore,
2(2x+3)(4x^2 - 6x + 9)

hope this helps~ :)

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