Math

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How high will a baseball that is thrown up into the air at 48 feet per second go if it starts its flight at a height 10 feet above the ground?

  • Math -

    height = -16t^2 + 48t + 10
    d(height)/dt = -32t + 48
    = 0 at max height
    32t=48
    t = 48/32 = 1.5

    so at 1.5 seconds,
    height = -16(1.5)^2 + 48(1.5) + 10 = 59.5 ft

    check my arithmetic

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