Calc
posted by Hannah .
How do you do the derivative of an inverse trig function?
arcsin (sqrt2/2)??

arcsin(sqrt2/2 ) is a constant. The derivative of a constant is zero.

oops mixed up 2 questionss haha

to find an arcsin you would just have to memorize the unit circle right? so arccos of sqrt3/2 is 5pi/6?

yes, that is the easy way.

However, to find the derivative of an inverse trig function, go through the back door, as it were
y = arcsin(x)
sin y = x
cos y y' = 1
y' = 1/cos x = 1/√(1sin^{2}x) = 1/√(1x^{2})
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