posted by Hannah .
How do you do the derivative of an inverse trig function?
arcsin(sqrt2/2 ) is a constant. The derivative of a constant is zero.
oops mixed up 2 questionss haha
to find an arcsin you would just have to memorize the unit circle right? so arccos of -sqrt3/2 is 5pi/6?
yes, that is the easy way.
However, to find the derivative of an inverse trig function, go through the back door, as it were
y = arcsin(x)
sin y = x
cos y y' = 1
y' = 1/cos x = 1/√(1-sin2x) = 1/√(1-x2)