Question

x/x+3-3/x-3=x^2+9/x^2-9

Answer 1

If I read this right, it's

x/(x+3) - 3/(x-3) = (x^2+9)/(x^2-9)

[x(x-3) - 3(x+3)]/(x^2-9) = x^2+9)/(x^2-9)

Now, x cannot be 3 or -3. With that in mind, we just need

x^2 - 3x - 3x - 9 = x^2 + 9
-6x = 18
x = -3

So, the only possible solution is x = -3, but that means we have 0/0.

No solutions exist.