A skydiver of mass 81.5 kg jumps from a slow-moving aircraft and reaches a terminal speed of 54.9 m/s.
(a) What is her acceleration when her speed is 30.0 m/s?
(b) What is the drag force on the skydiver when her speed is 54.9 m/s?
(c) What is the drag force on the skydiver when her speed is 30.0 m/s?
how do i figure out this problem? All I got was the R=(.5)pADv^2
maiking the first part a contant
R=Bv^2
R=mg
Bv^2=mg
king
To solve this problem, we can use the equation for the drag force on an object in free fall:
Drag force (R) = B * v^2
where:
- R is the drag force
- B is the drag coefficient (a constant that depends on the shape of the object)
- v is the velocity of the object
(a) To find the acceleration when the speed is 30.0 m/s, we need to determine the net force acting on the skydiver. Since the skydiver has reached terminal velocity, the net force is zero.
The net force is given by:
Net force = ma
In this case, since the net force is zero, the acceleration is also zero.
(b) To find the drag force when the speed is 54.9 m/s, we can substitute the given values into the formula for R:
R = B * v^2
R = B * (54.9)^2
(c) To find the drag force when the speed is 30.0 m/s, we can again substitute the given values into the formula for R:
R = B * v^2
R = B * (30.0)^2
Now, to find the value of B in both cases, we need to use the fact that at terminal velocity, the drag force is equal to the weight of the object:
R = mg
Given that the mass of the skydiver is 81.5 kg, and the acceleration due to gravity is approximately 9.8 m/s^2, we can solve for B as follows:
B * (54.9)^2 = 81.5 * 9.8
B * (30.0)^2 = 81.5 * 9.8
By solving these two equations, we can find the value of B.
Now, let's plug in the values and calculate the answers using the equations provided!