Pressure cooker is 1.3atm what is the temperature of water that boils
I don't have a vapor pressure vs T curve. If you have one in your text, look for T at 1.3 atm (988 mm Hg).
To determine the temperature at which water boils in a pressure cooker, you will use the relationship between pressure and boiling point temperature. The boiling point of a liquid increases with increasing pressure.
One commonly used equation to calculate the boiling point temperature is the Clausius-Clapeyron equation:
ln(P1/P2) = (ΔHvap/R)(1/T2 - 1/T1)
Where:
P1 and T1 are the initial pressure and temperature of the water
P2 is the pressure of the pressure cooker
T2 is the boiling point temperature in Kelvin
ΔHvap is the enthalpy of vaporization of water (40.7 kJ/mol)
R is the ideal gas constant (8.314 J/(mol·K))
Rearrange the equation to solve for T2:
T2 = (1/((ΔHvap/R)(ln(P1/P2)) + (1/T1)))
Given that the pressure cooker has a pressure of 1.3 atm, you can substitute P2 = 1.3 atm. The atmospheric pressure at sea level is approximately 1 atm, so you can assume P1 = 1 atm.
Assuming room temperature is around 25°C or 298 K, you can use T1 = 298 K.
Once you have these values, you can plug them into the equation and solve for T2 to find the boiling point temperature of water in the pressure cooker.