What is the axis of symmetry for the function? y = x^2 + 3x - 4
A. y = -2
B. y = -1.5
C. x = -2
D. x = -1.5
x= -1.5
Before you post more of these, just remember that the axis of symmetry is x = -b/2a
This comes right from the quadratic formula:
x = [-b +/- sqrt(b^2-4ac)]/2a
= -b/2a +/- sqrt(b^2-4ac)/2a
The roots are symmetrically located around the line x = -b/2a
The axis of symmetry for a quadratic function can be found using the formula x = -b/2a, where a, b, and c are the coefficients of the quadratic equation in the standard form ax^2 + bx + c.
For the given equation y = x^2 + 3x - 4, we can see that a = 1 and b = 3.
Now, substitute these values into the formula x = -b/2a:
x = -(3)/(2*1) = -3/2 = -1.5
Therefore, the axis of symmetry for the function y = x^2 + 3x - 4 is x = -1.5.
Hence, the correct answer is D. x = -1.5