Math
posted by Farrah .
For what values of k will the functon f(x)=kx^24x+k have no zeros
Determine the values of k for which the function f(x)=4x^23x+2kx+1 have 2 zeros

if b^2  4ac < 0 > no real zeros
if b^2  4ac = 0 > one real zero
ifb^2  4ac > 0 > two real zeros
if will do the 2nd question.
a=4, b= 2k3 , c = 1
b^2  4ac
= (2k3)^2  4(4)(1)
= 4k^2  12k + 9  16
= 4k^2  12k  7
= (k + 1)(4k  7)
(k+1)(4k7) > 0 for 2 real roots
k < 1 OR k > 7/4