algebra,math
posted by tracy .
Solve the equation. Check both solutions and only write the real solution.
the square root of 6m minus 5 = m
A. {1}
B. {5}
C. {1, 5}
D. no real solution
I think its B

√(6m)  5 = m
√(6m) = m+5
square both sides
6m = m^2 + 10m + 25
m^2 + 4m + 25 = 0
m = (4 ± √84)/2
no real solution
if you think it is B), why not check it
LS = √30  5
RS = 5
mmmhhh
However, if you meant:
√(6m5) = 5
then 6m5 = 25
6m = 30
m = 5
See what happens if you don't use brackets to avoid ambiguity? 
U tried bt itz wrong . .ansa iz a . . 6m  5 =m . Colect lyk terms . 6m m =5 . 5m =5 . Then m =1 .
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