# physics

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A long jumper leaves the ground at an angle of 25.2 to the horizontal and at a speed of
11.2 m/s.

How far does he jump? The acceleration
due to gravity is 9.8 m/s2 .

What maximum height does he reach?

• physics -

1. Dh = Vo^2*sin(2A) / g,
Dh = (11.2)^2*sin50.4 / 9.8 = 9.86m.

2. Yo = ver. = 11.2sin25.2 = 4.77m/s.

h = (Yf^2 - Yo^2) / -19.6,
h = (0 - (4.77)^2) / -19.6 = 1.161m

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