physics

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A stone is thrown horizontally at a speed of 4.8 m/s from the top of a cliff 88.5 m high.

How long does it take the stone to reach the bottom of the cliff?

  • physics -

    u = 0
    s = 88.5 m
    a = 9.8 m/s^2
    s = ut + 1/2 at^2
    88.5 = o + 1/2 9.8 * t^2
    = 4.9 * t^2
    t^2 = 88.5 / 4.9
    = 18.06
    t = 4.25
    Horizonal displacement = vt
    = 4.8 * 4.5
    =21.6 m

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