physics
posted by Anonymous .
A stone is thrown horizontally at a speed of 4.8 m/s from the top of a cliff 88.5 m high.
How long does it take the stone to reach the bottom of the cliff?

u = 0
s = 88.5 m
a = 9.8 m/s^2
s = ut + 1/2 at^2
88.5 = o + 1/2 9.8 * t^2
= 4.9 * t^2
t^2 = 88.5 / 4.9
= 18.06
t = 4.25
Horizonal displacement = vt
= 4.8 * 4.5
=21.6 m
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