Algebra
posted by JessieLynne .
Could someone please show me how to write this equation in standard form?
x^2 + y^2  6x+8y+9=0

That is the standard general form. Now, if you want it as a conic section in standard form, group the x and y terms:
(x^2  6x) + (y^2 + 8y) + 9 = 0
Now, make each parenthesized group a perfect square, then subtract off whatever you had to add in:
(x^2  6x + 9) + (y^2 + 8y + 16) + 9916 = 0
(x3)^2 + (y4)^2 = 16