Table salt, NaCl(s), and sugar, C12H22O11(s), are accidentally mixed. A 5.50-g sample is burned, and 1.80 g of CO2(g) is produced. What is the mass percentage of the table salt in the mixture?

To find the mass percentage of table salt (NaCl) in the mixture, we need to determine the mass of NaCl present in the 5.50 g sample.

First, let's calculate the moles of CO2 produced. We can use the molar mass of CO2 to convert grams to moles:

Molar mass of CO2 = (12.01 g/mol * 1) + (16.00 g/mol * 2) = 44.01 g/mol

Moles of CO2 produced = mass of CO2 produced / molar mass of CO2
= 1.80 g / 44.01 g/mol

Next, let's convert the moles of CO2 to moles of carbon in the sugar (C12H22O11). Since each CO2 molecule contains one carbon atom, we can equate the moles of CO2 to the moles of carbon:

Moles of carbon in sugar = moles of CO2 produced

Now, let's calculate the mass of carbon in the sugar:

Molar mass of carbon = 12.01 g/mol

Mass of carbon in sugar = moles of carbon in sugar * molar mass of carbon

Since the molecular formula of sugar is C12H22O11, we know that there are 12 carbon atoms in one molecule of sugar. Thus, the moles of carbon in the sugar can be divided by 12 to find the moles of sugar:

Moles of sugar = moles of carbon in sugar / 12

Now, we can calculate the mass of sugar:

Mass of sugar = moles of sugar * molar mass of sugar

Since we know that the mass of the 5.50 g sample consists of both NaCl and sugar, we can subtract the mass of sugar from the total mass to find the mass of NaCl:

Mass of NaCl = Total mass - Mass of sugar

Finally, let's calculate the mass percentage of NaCl:

Mass percentage of NaCl = (Mass of NaCl / Total mass) * 100%

Plug in the values obtained from the calculations to determine the mass percentage of NaCl in the mixture.

To find the mass percentage of table salt (NaCl) in the mixture, we need to calculate the mass of NaCl present in the 5.50 g sample.

First, we need to find the moles of CO2 produced. We know that the molar mass of CO2 is 44.01 g/mol, so let's calculate the moles of CO2 produced:

Moles of CO2 = mass of CO2 / molar mass of CO2
= 1.80 g / 44.01 g/mol

Next, we can determine the moles of C12H22O11 that were present in the sample. The molar mass of C12H22O11 is 342.3 g/mol.

Moles of C12H22O11 = mass of sample / molar mass of C12H22O11
= 5.50 g / 342.3 g/mol

In the chemical reaction, one mole of C12H22O11 produces 12 moles of CO2. Hence, the moles of NaCl produced will be equal to the moles of CO2 produced since NaCl does not produce CO2 in the reaction.

Moles of NaCl = Moles of CO2 = 1.80 g / 44.01 g/mol

Now, let's calculate the mass of NaCl:

Mass of NaCl = Moles of NaCl x Molar mass of NaCl
= (1.80 g / 44.01 g/mol) x (22.99 g/mol + 35.45 g/mol)

Finally, we can calculate the mass percentage of NaCl:

Mass percentage of NaCl = (mass of NaCl / mass of sample) x 100
= (mass of NaCl / 5.50 g) x 100