A sample of gas has an initial volume of 33.0 L at a pressure of 1.1 atm.
If the sample is compressed to a volume of 10.0 L, what will its pressure be? (Assume constant temperature.)
Use Boyles Law.
P1V1=P2V2
(33.0L)(1.1atm)=(P2)(10.0L)
and solve for P2.
To solve this problem, you can use Boyle's Law, which states that the pressure and volume of a gas are inversely proportional when the temperature is constant. Mathematically, this can be expressed as P1V1 = P2V2.
Given:
P1 = 1.1 atm (initial pressure)
V1 = 33.0 L (initial volume)
V2 = 10.0 L (final volume)
We need to find P2, the final pressure.
Using Boyle's Law, we can set up the equation:
P1V1 = P2V2
Substituting the given values:
(1.1 atm)(33.0 L) = P2(10.0 L)
Now, solve for P2:
P2 = (1.1 atm)(33.0 L) / (10.0 L)
P2 = 36.3 atm
Therefore, when the sample is compressed to a volume of 10.0 L, the pressure will be 36.3 atm.