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chemistry 105

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Lithium reacts with nitrogen gas according to the following reaction: 6Li(s)+N2(g)-->2LiN(s)
What mass of lithium (in g ) is required to react completely with 59.9 mL of N2 gas at STP?

  • chemistry 105 -

    Use the ideal gas law..
    PV=nRT
    and solve for moles of N2

    SO....
    (1.00atm)(.0599L)=n(0.0821L*atm/mol*K)(273K)
    solve for n.

    then use "n" moles of N2 and then set up an conversion factor.

    so....
    ___moles of N2 x( 6mol Li/2mol N2) x (MolarMass Li/1mol of Li)


    Then that gives you your mass of Lithium required to react.
    Hope that helps!

  • chemistry 105 -

    .555 g

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