write ionic equation for :

potassium carbonate and sodium sulfate
sulfuric acid and strontium chloride
potassium phosphate and sodium hydroxide
sodium hydroxide and strontium chloride

To write ionic equations for these chemical reactions, we need to first identify the ions present in the reactants and products.

1. Potassium carbonate and sodium sulfate:
The chemical formulas for potassium carbonate and sodium sulfate are K2CO3 and Na2SO4, respectively.

Step 1: Write the formula equation:
K2CO3(aq) + Na2SO4(aq) → ?

Step 2: Identify the ions present (using solubility rules):
Potassium carbonate dissociates into K+ and CO3^2- ions.
Sodium sulfate dissociates into Na+ and SO4^2- ions.

Step 3: Write the ionic equation:
K+(aq) + CO3^2-(aq) + 2Na+(aq) + SO4^2-(aq) →

Step 4: Balance the equation:
2K+(aq) + CO3^2-(aq) + Na2SO4(aq) → K2SO4(aq) + Na+(aq) + CO3^2-(aq)

2. Sulfuric acid and strontium chloride:
The chemical formulas for sulfuric acid and strontium chloride are H2SO4 and SrCl2, respectively.

Step 1: Write the formula equation:
H2SO4(aq) + SrCl2(aq) → ?

Step 2: Identify the ions present:
Sulfuric acid dissociates into H+ and SO4^2- ions.
Strontium chloride dissociates into Sr^2+ and 2Cl^- ions.

Step 3: Write the ionic equation:
2H+(aq) + SO4^2-(aq) + Sr^2+(aq) + 2Cl^-(aq) →

Step 4: Balance the equation:
2H+(aq) + SO4^2-(aq) + SrCl2(aq) → SrSO4(s) + 2HCl(aq)

3. Potassium phosphate and sodium hydroxide:
The chemical formulas for potassium phosphate and sodium hydroxide are K3PO4 and NaOH, respectively.

Step 1: Write the formula equation:
K3PO4(aq) + NaOH(aq) → ?

Step 2: Identify the ions present:
Potassium phosphate dissociates into 3K+ and PO4^3- ions.
Sodium hydroxide dissociates into Na+ and OH^- ions.

Step 3: Write the ionic equation:
3K+(aq) + PO4^3-(aq) + Na+(aq) + OH^-(aq) →

Step 4: Balance the equation:
3K+(aq) + PO4^3-(aq) + NaOH(aq) → Na3PO4(aq) + 3KOH(aq)

4. Sodium hydroxide and strontium chloride:
The chemical formulas for sodium hydroxide and strontium chloride are NaOH and SrCl2, respectively.

Step 1: Write the formula equation:
NaOH(aq) + SrCl2(aq) → ?

Step 2: Identify the ions present:
Sodium hydroxide dissociates into Na+ and OH^- ions.
Strontium chloride dissociates into Sr^2+ and 2Cl^- ions.

Step 3: Write the ionic equation:
Na+(aq) + OH^-(aq) + Sr^2+(aq) + 2Cl^-(aq) →

Step 4: Balance the equation:
Na+(aq) + OH^-(aq) + SrCl2(aq) → NaCl(aq) + Sr(OH)2(aq)

Please note that these equations may not represent the actual reaction conditions or stoichiometry; they are simplified ionic equations representing the overall ionic species involved.