Math
posted by Simon .
The length and width of a rectangle are (x+4) cm and x cm respectively. Write down expressions for:
A. The perimeter of the rectangle
B. The length of the side of a square with the same perimeter
If the sum of the areas of the square and the rectangle is 94 cm^2 , find x. Explain your working and solution

a) P = 2(x+4) + 2x = 4x + 8
b) if this had been a square, then each side would have been (4x+8)/4 = x+2
x(x+4) + (x+2)^2 = 94
x^2 + 4x + x^2 + 4x + 4 = 94
2x^2 + 8x  90 = 0
x^2 + 4x  45 = 0
(x+9)(x5) = 0
x = a negative or x = 5
check:
rectange was 5 by 9 for an area of 45
square was 7 by 7 for an area of 49
total area is 45+49 = 94 ,
all is good!