The equivalent weights of X and Y are _________ g/equiv. H+ and g/equiv. –OH, respectively, for the following reaction: Z
(Note: Report your answer with 4 significant figures.)
X Y Z Answer #1 Answer #2
benzoic acid calcium hydroxide 2 C6H5COOH + Ca(OH)2
2 H2O +Ca(C6H5COO)2
sulfuric acid ammonium hydroxide H2SO4 + 2 NH4OH
2 H2O + (NH4)2(SO4)
hydrochloric acid aluminum hydroxide 3 HCl + Al(OH)3
3 H2O + AlCl3
sulfuric acid calcium hydroxide H2SO4 + Ca(OH)2
2 H2O + CaSO4
Your question is not clear to me at all.
To determine the equivalent weights of X and Y in the given reaction, we need to calculate the amount of X and Y in grams that reacts with one equivalent of H+ and –OH ions, respectively.
To do this, we can use the stoichiometry of the reaction:
2 C6H5COOH + Ca(OH)2 → 2 H2O + Ca(C6H5COO)2
From the balanced equation, we can see that for every 2 equivalents of H+ used, we need 2 equivalents of C6H5COOH. Similarly, for every 2 equivalents of –OH used, we need 1 equivalent of Ca(OH)2.
Using the molar mass of the compounds involved, we can convert the equivalents to grams.
1 equivalent of H+ is the same as the molar mass of H+ in grams.
1 equivalent of –OH is the same as the molar mass of –OH in grams.
So, to find the equivalent weights:
For X (benzoic acid):
1 equivalent of H+ = molar mass of H+ = 1.007 g/equiv. (with 4 significant figures)
For Y (calcium hydroxide):
1 equivalent of –OH = molar mass of –OH = 17.007 g/equiv. (with 4 significant figures)
Therefore, the equivalent weights of X and Y are 1.007 g/equiv. H+ and 17.007 g/equiv. –OH, respectively.